
wt0vremr's Musical Crackme
Download MusicalCrackme.zip, 75 kb (password: crackmes.de) Browse contents of MusicalCrackme.zip ============================
Difficulty: 1 - Very easy, for newbies | RatingVotes: 8 View profile of wt0vremr » |
Solutions
Solution by cr4ckpaper, published 27. feb, 2012; download (2 kb), password: crackmes.de or browse.
cr4ckpaper has rated this crackme as boring.
Solution by Xartrick, published 10. feb, 2012; download (1 kb), password: crackmes.de or browse.
Xartrick has rated this crackme as nothing special.
Solution by negux, published 10. feb, 2012; download (5 kb), password: crackmes.de or browse.
negux has rated this crackme as nothing special.
The submission of solutions is closed.
Discussion and comments
negux 08. Feb 2012 | I sent my solution, i dont understand what did you mean whit no debuggin, i solve whit olly thats ok?? :) |
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Xartrick 08. Feb 2012 | Solution sent: static analyze. |
wt0vremr Author 09. Feb 2012 | negux, depends on what you exactly did. |
negux 09. Feb 2012 | I find the instructions that generate the serial, and I programmed a little keygen, no patching |
lheer 10. Feb 2012 | thanks.wt0vremr i find id/serial. 570/932* I don't understand 'No debugging' |
Spl3en 10. Feb 2012 | 'No debugging' = 'Don't modify the binary' ? Funny music ! :) |
DimitarSerg 10. Feb 2012 | Thanks for keygenme. My source http://pastebin.com/hDCRpWWS |
agnsaft 12. Feb 2012 | This one is easy, but also really funny. Thanks for the Crackme! |
loneferret 13. Feb 2012 | I enjoyed it... didnt make a keygen or anything. Piece of paper and calculator was as far as I went. |
cr4ckpaper 15. Feb 2012 | Good challenge, a bit too easy, but none the less was a good welcome back to crackmes. |
fungsclup 19. Feb 2012 | can someone record a video? |
needhash 25. Feb 2012 | thanks, wt0vremr) |
sys_cc 01. Mar 2012 | y=6x+5903; it is very easy |
wt0vremr Author 01. Mar 2012 | I do not understand it, really. When I say "Very Very Easy" in the description, each is committed to repeat it in comments :) What for? :) |
wellwet 01. Mar 2012 | I solved it (e.g. 1/5909) but one thing I don't understand why is in function which generates serial add edx, 3 .... imul ebx, edx. Why edx equals 0? Where is in code it set? |
KryDos 01. Mar 2012 | Thanks. Solution (Perl) http://pastebin.com/WDKVxxCt |
wt0vremr Author 02. Mar 2012 | KryDos, comments is not the place for solutions, read the FAQ. |
Kostya 18. Apr 2012 | For those who don't understand why EDX = 0 after GetDlgItemInt. For this case when we call GetDlgItemInt it successfully translates TEXT from editbox to INT, we will get lpTranslated paramater in EDX which is NULL (because it doesn't care about translation errors). And if error happens it will return last int of translated char in EDX and EAX = 0. There is only one error that can happen it is overflow in Serial editbox. Since the max number of ID is 9999 we won't get overflow in Serial and EDX will allways be zero for correct Serial; btw, we can enter any count of leading zeros, because StrToInt("0001") = 1; |
Icebeen 06. Sep 2012 | As my first very first crack, I'd say this is a great beginner's start. |
dckjns 26. Jan 2013 | Very beginner friendly Assumed EDX to be 0 though and had to go look it up in a debugger |
seVeb 23. Jun 2013 | Thank you very much for making this crackme! This was actually my first i was able to keygen :) |
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