unicorn's Crackme1
| Download crackme1.zip, 44 kb (password: crackmes.de) Browse contents of crackme1.zip Very simple crackme for beginners..........
Difficulty: 1 - Very easy, for newbies | Send a message to unicorn » View profile of unicorn » |
Solutions
Solution by MiniMinou, published 27. jun, 2006; download (7 kb), password: crackmes.de or browse.
MiniMinou has rated this crackme as awesome.
Solution by c_07, published 22. jun, 2006; download (3 kb), password: crackmes.de or browse.
c_07 has rated this crackme as awesome.
Solution by Ank83, published 22. jun, 2006; download (8 kb), password: crackmes.de or browse.
Ank83 has rated this crackme as awesome.
Solution by znycuk, published 22. jun, 2006; download (4 kb), password: crackmes.de or browse.
znycuk has rated this crackme as quite nice.
The submission of solutions is closed.
Discussion and comments
| znycuk 18. Jun 2006 | easy one, but serial calculation is cool... maybe i will write a solution |
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| Ank83 18. Jun 2006 | Hi I'm having some problems with this crackme. The code is clear and simple, but I think that this one has not have valid serial. Am I right or I got lost in the code. Did some one try it. Where did I went wrong ? Need some help. Thanks and Best Regards Ank83 |
| znycuk 18. Jun 2006 | it have a good serial, at least one. i've submitted a solution this am. ;) |
| c_07 18. Jun 2006 | It took me forever to figure out the correct serial. I knew exactly what the serial verification algorithm was doing, but after a couple hours of trying to come up with one that fit the criteria -- including writing a bruteforce keygen in C++ -- I got pretty frustrated :). However, there is a correct serial (I think there is only one), that can be found by keeping in mind that the 10 digits of the correct serial MUST add up to 10 (I can't really explain the reason for this w/o a tutorial). If I would have known that in the first place it would have saved me a headache. :) Oh well. Great work unicorn! |
| Ank83 19. Jun 2006 | Hm... I will look at it once more and am giving up - I will wait for solution. I know that the serial must be of 10 digits, and there is some procedures that countes how many number are repeating and stuff but I can't fully understand the critierium. I was so long hook on VB targets that I forgot how to use my barin. :) Best Regards Ank83 |
| Ox87k 19. Jun 2006 | unicorn but there is only one serial? I found only 1. |
| snat 19. Jun 2006 | found one! great work |
| unicorn Author 20. Jun 2006 | Yeah there is only one serial .Thank u all for trying this crackme. |
| megadoctor 27. Jun 2006 | damn i cracked it... but it took me for about 2 hours... |
| MiniMinou 27. Jun 2006 | Good one to start with if you are a newbie, the code is quite clear, must use your brain a bit to find the serial but there is nothing to complicated ! |
| predador 26. Jul 2006 | I put nop´s in two lines to solve the problem...next level...newbie++...hehe |
| unicorn Author 31. Jul 2006 | Patching is LAME.... U can find the serial if u have a working brain :) |
| EuSo 13. Nov 2006 | o.O I edit "PUSH 0B" to "PUSH 00" an invert the 3 jumps from "jne to je" and "je to jne" and now its woks with any serial. As example: 1 :P ;) |
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