The So;X's The So;X 3 way crackme
| Download The_Sox_3_Way_Crackme.zip, 83 kb (password: crackmes.de) Browse contents of The_Sox_3_Way_Crackme.zip Go solve this
Difficulty: 3 - Getting harder | Send a message to The So;X » View profile of The So;X » |
Solutions
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Discussion and comments
| T.0.R.N.A.D.0. 14. May 2009 | I'm back after a long time :) Hey So;X I think I found a bug (or may be I'm missing something) : You accept names that are at-least 8 chars long. So, how do you expect to extract a sub string like this: Name.Substring(3,7) ?!? That would require names to be at-least 10 chars long !! |
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| T.0.R.N.A.D.0. 14. May 2009 | One more : You do not change Me.aaa, Me.bbb, Me.req1, Me.req2 to empty strings ("") in the Button1_Click sub, before checking for the conditions that set them to appropriate values. |
| The So;X Author 14. May 2009 | oh sorry dude i miss understood substring function ,... please those who are downloaded this crack me put 10 char long string in to it.... sorry for my ignorance. Tx T.0.R.N.A.D.0 |
| obnoxious 14. May 2009 | am i missing some thing Convert.ToBoolean("τ123") how can that be done??? |
| The So;X Author 19. Jul 2009 | come on ... No solutions.... :( |
| MrGneissGuy 02. Aug 2009 | The S0;X The reason there's no solution for you crackme is that it's impossible to solve. in your keyckeck, there 4 conversions to boolean that are impossible. The ONLY strings that can be converted to boolean are "true" and "false". The code can't be executed, so it falls back on the catch which tells us it's the wrong key. You can fix it if you like, but I don't know what you had intended. |
| The So;X Author 06. Aug 2009 | This is what u see in reflector If (((((Me.TextBox3.Text = (sol1 & Me.aaa)) = Conversions.ToBoolean(("chk" & Me.bbb))) = Conversions.ToBoolean(("chk" & Me.req1))) = Conversions.ToBoolean((ChrW(964) & Me.req2))) = Conversions.ToBoolean(ChrW(964) & "123")) Then Interaction.MsgBox("Your copy is registered" & ChrW(13) & ChrW(10) & "Way to go my freiend.......", MsgBoxStyle.OkOnly, Nothing) This is what i actually written If TextBox3.Text = sol1 & aaa = "chk" & bbb = "chk" & req1 = "τ" & req2 = "τ123" Then MsgBox("Your copy is registered" & vbNewLine & "Way to go my freiend.......") |
| obnoxious 07. Aug 2009 | yes but you are still missing on the parenthesis!!!!!! |
| The So;X Author 08. Aug 2009 | ya i know.... may be i am missing or may be not....:) |
| The So;X Author 08. Aug 2009 | as u all can see this is kind of misunderstanding reflector creates...It does not show what actually written... |
| Mayhem 06. Dec 2010 | Due to having copied most of the code from Reflector and making a keygen/reg value creator and the crackme still not accepting the serial it produces I have to conclude that it does indeed fall back on the catch. This was further confirmed when I edited the code with Reflexil to see exactly what as going on. If anyone can prove this wrong I will be very happy as it annoyed me somewhat when I realized what was happening. |
| bLaZeD 26. Feb 2011 | done: http://i.min.us/ijCsUC.png |
| Mayhem 26. Feb 2011 | @bLaZeD: Not quite, see readme... Rules : * No Patching (as always) * you'll need to make key gen |
| bLaZeD 09. Apr 2011 | I don't get rules, crackmes are to test security. If someone can patch your program, and get past it; It's cracked. |
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