malfunction's Digital Arithmetic
| Download malfunc_crk5.zip, 8 kb (password: crackmes.de) Browse contents of malfunc_crk5.zip Description inside
Difficulty: 5 - Professional problem to solve | Send a message to malfunction » View profile of malfunction » |
Solutions
Solution by andrewl.us, published 18. feb, 2009; download (69 kb), password: crackmes.de or browse.
andrewl.us has rated this crackme as awesome.
Discussion and comments
| cyclops Moderator 29. Nov 2008 | Good crackme! I just love the whole lot of SEH ;) |
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| kao 01. Dec 2008 | Hehe, Malfunction is back! :) I missed your crackmes! And now I got a good reason to brush up my keygenning skills.. |
| _HellDashX_ 02. Dec 2008 | A very nice crackme. I have it dumped, and a very nice SEH , :) |
| xpoy 07. Dec 2008 | well,i just love ur "call".tell me something,good crackme and finshed all game.but just lazy too translate test to english look here http://bbs.pediy.com/showthread.php?p=546760 |
| mjesun 07. Dec 2008 | oh god, I don't know... japanese :D |
| simonzack Moderator 12. Jan 2009 | finally killed all seh and close to solving nice refreshment after so long time not cracking anything |
| simonzack Moderator 12. Jan 2009 | lol i sound a bit stupid i mean nice crackme! |
| simonzack Moderator 21. Feb 2009 | as the key can read/write to itself, this makes the crackme a bit too easy (i'm not sure if this is on-purpose) the keyfile can simply store the ecx value in one bit, save the results of the name hashes, then compare with ecx to see which value to output, so simply: switch(ecx){ case 0: ... case 1: ... ... } though this can be very big, i read andrewl's solution, which contains xor this can be a specific case of the whole keyfile is this intentional? |
| simonzack Moderator 21. Feb 2009 | umm, now i'm not sure if above works (since there can be no jumps in file), but the following definitely should: use constants in round to load everything, 'and'ed with first 8 bytes (so future rounds constants are not loaded), then shift all values left by 8 bytes wipe out first 8 bytes with 0 therefore we have: for each round the hashed value is shifted in |
| tony 05. Jun 2009 | aha! I found an other method, thanks you ,'andrewl.us',your mind is very good ,but it can be simplified .you let me learn more,and have a inspiration. |
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