LaFarge's Crackme v0.2
| Download lafarge__s.crackme.0.2.crackme-icu.zip, 34 kb (password: crackmes.de) Browse contents of lafarge__s.crackme.0.2.crackme-icu.zip Easy crackme (??) for newbies who wanna learn keygenning.
Difficulty: 1 - Very easy, for newbies | Send a message to LaFarge » View profile of LaFarge » |
Solutions
Solution by red477, published 24. jan, 2006; download (5 kb), password: crackmes.de or browse.
red477 has not rated this crackme yet.
Solution by Ox87k, published 22. jan, 2006; download (53 kb), password: crackmes.de or browse.
Ox87k has not rated this crackme yet.
Solution by Kerberos, published 22. jan, 2006; download (39 kb), password: crackmes.de or browse.
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The submission of solutions is closed.
Discussion and comments
| astigmata 20. Jan 2006 | easy keygenme point H, F8, serial in stack. I ll look how it's generated thx 4 n00b |
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| Ank83 20. Jan 2006 | Hi, I'm missing one part of the app ! I didn't understand it. I will look it again. If some one has the key what is happening on the IDIV EBX line please help me. Here is the code: Dim Cons, Name, Char, Char1 As String Dim Xored, Xored1 As Integer Cons = "_r <()<1-Z2[l5,^" Name = Text1.Text Text2.Text = "" While Len(Name) < 16 Name = Name & Name Wend For i = 1 To Len(Cons) Char = Mid(Name, i, 1) Char = Asc(Char) Char1 = Mid(Cons, i, 1) Char1 = Asc(Char1) Xored = Char Xor Char1 'MISSING PART 'MISSING PART If Abs(Xored1) <> Xored1 Then Xored1 = Xored End If Xored1 = Xored1 + 65 Text2.Text = Text2.Text + Chr(Xored1) Next i Thanks and regard Ank83 |
| astigmata 20. Jan 2006 | 004011EE CDQ // convert double to quad 004011EF IDIV EBX //integer divide I try to understand me too but :P |
| Kerberos 20. Jan 2006 | In EAX you have I-th char your name XORed with I-th char from that constant string, EDX = 0 and EBX = 0x19 so IDIV EBX ... EAX = EAX / EBX EDX = EAX % EBX |
| astigmata 20. Jan 2006 | damn, you right Kerberos I didn't know that, thank U. |
| astigmata 20. Jan 2006 | selfkeygen Patches Address Size State Old New Comment 0040120B 8. Active MOVS DWORD PTR ES:[EDI],DWORD PTR DS:[ESI] JMP crackme.0040128E 00401290 5. Active PUSH crackme.0040630C PUSH EDI |
| Ox87k 21. Jan 2006 | i submitted my solution yesterday... however thanks 4 this crackme lafarge! g00d j0b! |
| Kerberos 22. Jan 2006 | Hey red477, you've nice keygen, but it doesn't works well for all inputs :-/ For example on input : "1234567890321456987777778" your serial key is KOTI-EGLJ-UGBF-SBAE, but correct key is OTYB-OMXA-JGBF-SBAE :-/ |
| red477 23. Jan 2006 | Kerberos,Yes,u r quite right and thank you very much for tell me this.and i made such a big mistake on this little simple crackme...:( i will improve myself in my later solutions. but probably after a time coz i am a little occupied for now. |
| red477 24. Jan 2006 | and again a little problem on Ox87k solution.it wont generate key for inputs whose length is exactly 26.for example "12345678903214569877777781"=>"OTYB-OMXA-JSBF-SBAE".that's it (such a small flaw)and i really learned a lot from all of you.thank you. :) |
| red477 24. Jan 2006 | since i dont want to send a newer version of solution again so i will leave maybe my last comment on my solution here:the solution is still not perfect,you will still find bugs(i have found some:)). |
| toshimi 25. Jan 2006 | ZZZzzzz.. very easy..!!! thanks LaFarge's |
| Jailani 14. Feb 2006 | How do i submit the key gen here well i did,nt write the solution i made the keygen but i can explain what i used i can paste the coding i used it is ser = "0000000000000000" tl = 0 a = "_r <()<1-Z2[l5,^" b = Trim(Text2.Text) If Len(a) > Len(b) Then tl = Len(a) Else tl = Len(b) For i = 0 To tl - 1 ai = (i Mod Len(a)) + 1 bi = (i Mod Len(b)) + 1 seri = (i Mod 16) + 1 Mid(a, ai, 1) = Chr(((Asc(Mid(a, ai, 1)) Xor Asc(Mid(b, bi, 1))) Mod &H19) + &H41) Mid(ser, seri, 1) = Mid(a, ai, 1) Next i For i = 1 To 16 Step 4 sr = sr & Mid(ser, i, 4) & "-" Next i Text1.Text = Mid(sr, 1, Len(sr) - 1) |
| Jailani 15. Feb 2006 | Its just Xor Algorithm is,nt It |
| r-Evolution 05. Oct 2010 | What a nice and interesting keygenme...I suppose i am gonna write my first keygen on it!!!! |
| r-Evolution 08. Nov 2010 | i finished the keygen now..Solution on the way |
| r-Evolution 08. Nov 2010 | @jailani xor eax, edx eax % 0x19 eax + 0x41 |
| aldeid 05. Dec 2015 | My solution posted here: https://www.aldeid.com/wiki/Solution-LaFarges-crackme-2 |
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