ksydfius's DCTF 4
| Download dctf4.zip, 93 kb (password: crackmes.de) Browse contents of dctf4.zip Here is a challenge I wrote for DefCamp earlier in November.
Difficulty: 2 - Needs a little brain (or luck) | RatingWaiting for at least 3 votes View profile of ksydfius » |
Solutions
Solution by baderj, published 13. nov, 2014; download (63 kb), password: crackmes.de or browse.
baderj has not rated this crackme yet.
Discussion and comments
| maximcff 20. Dec 2013 | hey, is there a way to find a key except bruteforcing? i've understood the algo, but.. it's a trouble to find a key :B |
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| ksydfius Author 20. Dec 2013 | You need to make certain assumptions. Think about smart brute force. |
| maximcff 22. Dec 2013 | a stupid question.. :) the password is digital, or digits+letters, or smth else? |
| ksydfius Author 23. Dec 2013 | digits+letters (upper+lower) |
| maximcff 25. Dec 2013 | 6-character bruteforcing didn't have success :( |
| ksydfius Author 25. Dec 2013 | Password length is way too long for brute force directly. You need a smart way to get the password. Make some assumptions. Once you understand the idea here, you'll find the answer quickly enough. |
| maximcff 27. Dec 2013 | ok, i've found a new way) now bruteforce is not direct. tell me please, the password's length <= 10, but >= 8? |
| ksydfius Author 28. Dec 2013 | password length is > 20 :) |
| maximcff 28. Dec 2013 | it's bad :( tell me please, array1[0x70] and array2[0x59] before encoding are just binary data, or also digits and letters? |
| ksydfius Author 29. Dec 2013 | Those are the assumptions you need to make... |
| maximcff 01. Jan 2014 | _W34kAlG0R1ThM5aR3b4dF0rY0U_ yeahh :) submit this) |
| ksydfius Author 01. Jan 2014 | Nice work, maximcff :) |
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