jockcranley's T0AD K3YG3N
| Download T0ADK3YG3N.zip, 29 kb (password: crackmes.de) Browse contents of T0ADK3YG3N.zip Key Generator.
Difficulty: 1 - Very easy, for newbies | RatingWaiting for at least 3 votes View profile of jockcranley » |
Solutions
Solution by aldeid, published 10. dec, 2015; download (107 kb), password: crackmes.de or browse.
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Solution by Kaltwa55er, published 22. jul, 2015; download (2 kb), password: crackmes.de or browse.
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Solution by vigilanz, published 19. may, 2015; download (2 kb), password: crackmes.de or browse.
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Discussion and comments
| downabc 03. May 2015 | great one, but did you forgot to verify the 9 char of the password. your algorithm calculate a password contained 9 chars , but only verified the first 8 chars. |
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| Kaltwa55er 15. Jun 2015 | I think the algorithm just checks to see if there are 8 characters being used in the username and ignores anymore. Password should be 8 characters long also. |
| Parad0xD9 25. Jun 2015 | Really fun! My first keygen. Thanks jockcranley. |
| acruel 01. Jul 2015 | If you input only 8 chars, the 9th char will be \x0a. I think the program expect 9 chars input. |
| Kaltwa55er 03. Jul 2015 | Guess it depends if your counting the carriage/Null terminator as the 9th characater |
| zbychu 22. Jul 2015 | Nice :-) But IMO algorithm is buggy, anyway solved ;p |
| fdjkf 29. Aug 2015 | very interesting fgets(*s,size,*stream) only accepts the first size-1 bytes,and ends the string you input with 0x00,so only 8 chars is ok. and the username is 7 bytes by using the printf() after fflush() after fgets(),very ood…… |
| aldeid 05. Dec 2015 | My solution posted here: https://www.aldeid.com/wiki/Solution-jockcranley-T0AD-K3YG3N |
| luxdav 31. Aug, 11:51 | my solution: https://github.com/LuxXx/reverse-engineering/tree/master/toad |
| rni123 20. Nov, 21:11 | Unfortunately, the MacOSX binaries do not work correctly (never stops on the password input, just exits immediately with access denied message) on my OSX-10.11, so I quickly ran Hopper-4 and generated the following pseudo-code, after renaming some cryptic variables: http://pastebin.com/BxbZjYFc. From a first quick glance, I suppose that the username has to have at least 9 chars and that the password is following the convention at loc_100000d68, which roughly translates to (algorithm for the keygen): int mult = var10 / 3; // var10 is unclear, probably due to r8d could be oldpass[1] for (int i = 0; i <= 8; i++) { int tmp = oldpass[i]; newpass[i] = ((mult ^ tmp) & 60) + 48; mult = 3 * ((mult ^ tmp) & 60); } Since I can't test it, writing a keygen is pointless at this point. |
| Mithreindeir 23. Nov, 02:13 | Only the windows version works, fun keygen though. |
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