halsten's CrackME2
| Download crackme_2.zip, 4 kb (password: crackmes.de) Browse contents of crackme_2.zip Just like the previous CrackME1, now it's getting a little harder. Write a keygen for it.
Difficulty: 1 - Very easy, for newbies | RatingVotes: 4 View profile of halsten » |
Solutions
Solution by marius_mtm, published 21. apr, 2007; download (2 kb), password: crackmes.de or browse.
marius_mtm has rated this crackme as quite nice.
Solution by BaKaE, published 19. feb, 2007; download (207 kb), password: crackmes.de or browse.
BaKaE has rated this crackme as quite nice.
Solution by Kostya, published 08. feb, 2007; download (4 kb), password: crackmes.de or browse.
Kostya has rated this crackme as quite nice.
Discussion and comments
| halsten Author 01. Feb 2007 | There's something funny about this one. :] |
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| hardcoder 01. Feb 2007 | Mate, don't mind, 3 is tooooooooooo much high ranking for this cm, nothing special except code obfuscation. regards |
| Kostya 01. Feb 2007 | ..maybe because the last one was a bit easyer, so now it is getting harder!? :) but algo looks the same :), i mean about keygenning :P, btw solution sent.. :) |
| halsten Author 02. Feb 2007 | It's meant to be for beginners, not everyone is as good as you might be, that's it. |
| BaKaE 02. Feb 2007 | yes 3 is tooooo high, for everyone. btw this funny thing, is this the wrong crackme name ?? caus its still crackme1 ;) |
| halsten Author 02. Feb 2007 | Yes, it's the wrong name, I forgot to change the old name from my template skeleton file. |
| Devoney 05. Feb 2007 | Deffinitly not 3-Getting Harder. At most 2- Need a little brain of luck. The checkup after the second GetDlgItemText call is way to simple. A username and password of 4 chars is enough. And only 2 chars of the username are changed to be equal to the password. Besides the difficulty rating being not correct this crackme is good for beginners like me. Thanks for creating it. Lot of code though for assembler! |
| hound 08. Feb 2007 | Im not familar at all with obfustication :(. A good tutorial would be great from someone who solved it (or any other tutorial/reading links). |
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