Greedy_Fly's Night In Odessa
| Download KeygenMe.zip, 38 kb (password: crackmes.de) Browse contents of KeygenMe.zip Hi, All...
Difficulty: 4 - Needs special knowledge | RatingWaiting for at least 3 votes View profile of Greedy_Fly » |
Solutions
Solution by s3Rious, published 24. sep, 2013; download (21 kb), password: crackmes.de or browse.
s3Rious has rated this crackme as nothing special.
Solution by demoth, published 05. sep, 2013; download (29 kb), password: crackmes.de or browse.
demoth has rated this crackme as boring.
Discussion and comments
| idid231 04. Sep 2013 | Can i have a real combo for this keygenme? As i coded my kgm, hard to find a name which has a serial. |
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| demoth 04. Sep 2013 | idid231, for example: name: demoth serial: 29E7E9B5A |
| idid231 05. Sep 2013 | Very well, your key is good, thank you demoth, i need to see why my keygen doesn't work. |
| idid231 06. Sep 2013 | So quick! I still don't know where i'm wrong even read your solution. As i know Input serial is: yEx My name: Lovemagic gives 01461C3F => x = 1C3F i compute my serial: y = (x + 0x7E) div 4 (i changed div 4 to shr,2 too) y = y xor 0x2EC9 => y = 0x29E6 but in keygen: Lovemagic has 69E6 as serial i wonder where i'm wrong, look at demoth's src i see my code is same as his |
| demoth 06. Sep 2013 | 01461C3F => x = 1C3F, y = 0146 x1 = ror2(x + 0x7E) ^ 0x2EC9; y1 = (y ^ 0x4DE2) << 1; |
| idid231 06. Sep 2013 | i see, it's in your source code, but as i said x1 = ror2(x + 0x7E) = (0x1C3F + 0x7E) div 4 = 72F 0x72F xor 0x2EC9 = 29E6. Your keygen gives me 69E6 instead, could you please help me find where i'm wrong. |
| demoth 06. Sep 2013 | ror2 != div 4. div 4 equals shr 2. If you're coding in vb you need something like this for ror2: (val div 4) + (val mod 4) * (2 ^ 14) |
| idid231 07. Sep 2013 | Great, Thank for your info! |
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