DaXXoR 101's KeygenMe #4
| Download KeygenMe#4.zip, 7 kb (password: crackmes.de) Browse contents of KeygenMe#4.zip Write a program that can generate valid keys.
Difficulty: 5 - Professional problem to solve | Send a message to DaXXoR 101 » View profile of DaXXoR 101 » |
Solutions
Solution by _HellDashX_, published 25. aug, 2005; download (24 kb), password: crackmes.de or browse.
_HellDashX_ has rated this crackme as quite nice.
Solution by bRaiN_faKKer, published 23. aug, 2005; download (4 kb), password: crackmes.de or browse.
bRaiN_faKKer has not rated this crackme yet.
Discussion and comments
| GR33d 02. Aug 2005 | hi ok ... im a half noob just got some keygen mes a bit harder and this is one... if i stay on level 1-2 keygenmes ill never get n better on reversing, so i tryed this one .... ok the protection(packed) is gone so now.... the algo.. ok i already figured it out.. but i just couldnt find a way to reverse it!! it has some un-reversible checksum on the serial inserted.... im a bit confused... about this one, cus i cant reverse it ! daxxor can u help me out ? |
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| DaXXoR 101 Author 02. Aug 2005 | hey Gr33d, ok let me give you a hint, this is how you'd keygen the last serial box. checksum = CMP BH,1E rite? say ebx is 00001E00 at the end, that means all you have to do is perform all the steps it did to get the final result backwards. That also means the other parts of ebx can be any number. thats how we get different keys. Heres a valid key: 91B512A707-021222682H-1FF46L5220-2067120286 good luck! |
| GR33d 02. Aug 2005 | great ! thats a big help :) but, i did try to reverse the 4 algos(ithink there are 4) whitout n sucess, it is still missing something... ill keep trying thx 4 the help :D |
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