
cyclops's KeyGenMe-iNF1
Download KGenMe-iNF1.zip, 4 kb (password: crackmes.de) Browse contents of KGenMe-iNF1.zip Small Krypto KeyGenMe.
Difficulty: 3 - Getting harder | RatingWaiting for at least 3 votes View profile of cyclops » |
Solutions
Solution by crp-, published 24. sep, 2006; download (7 kb), password: crackmes.de or browse.
crp- has not rated this crackme yet.
Discussion and comments
HMX0101 18. Sep 2006 | Very easy, nice job cyclops... Maybe i write a tut+keygen this week :) |
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geeko 20. Sep 2006 | must the geygen accept any string in the 'name' box? or just those which have some property? |
geeko 20. Sep 2006 | or can I generate pairs of name/key? |
cyclops Moderator 20. Sep 2006 | Itz a keygenme...SO it has to accept any string in name. Whatz the property? |
m@rio_crk 20. Sep 2006 | nice try HMX0101 :) - "Dont patch, brute-Force....." |
HMX0101 20. Sep 2006 | Hehe, i didn't find another way to solve it :P I'm not very good with the maths :) |
jB_ 21. Sep 2006 | HMX0101: check modular arithmetic algorithms on google. A very well known algorithm may help you. |
geeko 21. Sep 2006 | I riched the step as HMX did, but didn't upload coz it's brute force. Why not brute force dirrectly the serial into the edit box? |
geeko 21. Sep 2006 | cyclops, are u satisfied? |
geeko 21. Sep 2006 | the problem is resolving this equation: (a*x+1)/b=z find out a pair of (z,y) integers. Knowing thet a and b are integers too. I couldnt do without brutforce, could you? |
geeko 21. Sep 2006 | I think it can't be done |
cyclops Moderator 21. Sep 2006 | Hmm... I was out of station for some time.So... @HMX0101: Sorry ur solution violates "Patch/Brute Force". Plz follow what jB has said. @MOD: Plz DELETE the DOLUTION By HMX0101.I think i have given the details abt the keyge. @geeko: Itz not impossible.try harder. @jB & mario: I know u guyz have already solved it...dont you?? |
jB_ 21. Sep 2006 | cyclops: of course. It was not really challenging, but ok. One of the routines every beginner has to learn :) I will send you the keygen tomorrow if you're interested. |
HMX0101 21. Sep 2006 | Sorry, i going to study this method to solve it and submit it later... |
crp- 21. Sep 2006 | the crackme has a small bug. for roughly 1/0x1234th of all possible names, no valid serial exists. |
cyclops Moderator 24. Sep 2006 | THANKS FOR TRYING THIS CRACKME.... |
HMX0101 24. Sep 2006 | I can't found an algorithm to solve this :( |
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