costy's FOUR ACES
| Download poker.zip, 9 kb (password: crackmes.de) Browse contents of poker.zip Poker Crackme: you have to patch in order to get four (4) ACES. Each card can appear only ones. For example the program can't show two kings of heart.
Difficulty: 3 - Getting harder | RatingWaiting for at least 3 votes View profile of costy » |
Solutions
Solution by synak, published 25. may, 2010; download (1215 kb), password: crackmes.de or browse.
synak has not rated this crackme yet.
Discussion and comments
| Xspider 20. May 2010 | ouh looks like a nice one :D |
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| obnoxious 20. May 2010 | nice as usual :) |
| costy Author 20. May 2010 | I think my crackmes have always something special ;) |
| Xspider 20. May 2010 | yep they actually do :) |
| synak 23. May 2010 | this was fun, thanks! i've got the successful msg after getting myself four different 1's (aces), but the criteria to ensure the cards only appear once (including the CPU's hand) is something I'll leave to someone else..:) |
| costy Author 24. May 2010 | Continue practice synak!! Why don't you try to give to the CPU and to the player always the same cards? ;) |
| Xspider 25. May 2010 | hhhh you made it show more than 7 aces :p nice solution synak ;) |
| costy Author 25. May 2010 | I just finished to read the solution you posted privately and now it's published. It's a good solution. I hope you explain it better to me. ;) |
| synak 27. May 2010 | I got a little lazy and didn't explain how I knew EBP-18 was the current card count (1-10). Here is the additional detail: Shortly after the Rand() function is called, I noticed this: 0040BB0F MOVSX ESI,WORD PTR SS:[EBP-18] 0040BB13 CMP ESI,0B 0040BB16 JB SHORT 0040BB1E Ths is checking to see how many times the random card generation function has been called, compares it to 0Bh (11decimal), and jumps (continues generating cards) if we're still under 11. There are 10 cards in total being generated, so it was safe for me to assume that EBP-18 at this point in the code will contain the current amount of cards that have been generated so far. Knowing that, I used EBP-18 instead of writing code to do my own counting within the code cave. |
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