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costy's Balls by COSTY
Download balls.zip, 4 kb (password: crackmes.de) Browse contents of balls.zip You have to put the balls in the right boxes.
Difficulty: 1 - Very easy, for newbies | Send a message to costy » View profile of costy » |
Solutions
Solution by sd333221, published 07. jul, 2008; download (91 kb), password: crackmes.de or browse.
sd333221 has not rated this crackme yet.
Solution by Zaphod, published 07. jul, 2008; download (192 kb), password: crackmes.de or browse.
Zaphod has not rated this crackme yet.
Solution by Xspider, published 07. jul, 2008; download (34 kb), password: crackmes.de or browse.
Xspider has rated this crackme as awesome.
Discussion and comments
costy Author 04. Jul 2008 | Have you tried it? What do you think about? |
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DigitalAcid 04. Jul 2008 | Well, you could have chosen a less perverted name :). |
costy Author 04. Jul 2008 | Sorry if i hurted you. :-) |
Zaphod 04. Jul 2008 | It is very easy to solve by trial and error. THINKING a solution might be quite another thing... |
costy Author 04. Jul 2008 | Excuse me... If you wanna solve by trial and error, it's still needed a bit of analizing. The possibilities are 10! = 10*9*8*7*6*5*4*3*2*1 = 3628800. I don't think you can solve this only by trial and error. If you founded the solution you analized the code a bit. So post a solution. :-D |
Zaphod 04. Jul 2008 | Of course, costy, you are right, what I meant to say was "...by trial and error with the help of Olly". What I did isn't worth writing a solution about. Instead I'm trying to find out what the function "__vbaFpR4" does, but I cannot find an explanation anywhere. And I know VERY little about Visual Basic... |
costy Author 04. Jul 2008 | @Zaphod Any solution is acceptable :-D |
DigitalAcid 04. Jul 2008 | @Zaphod: It's probably something with floating point... |
Zaphod 05. Jul 2008 | OK, I'll write a short solution, consisting of 5 seconds of analysis and 5 minutes of trial and error, then we'll see if "any solution is acceptable" :) |
Zaphod 05. Jul 2008 | @DigitalAcid: You are probably right about the floating point, but it is strange that I cannot find an explanation about a Visual Basic-function... |
Zaphod 05. Jul 2008 | Solution submitted:) |
MACH4 05. Jul 2008 | @Zaphod, Nothing surprises me with the msvbvm60.dll You have to disassemble it to understand what the functions are doing! r4 refers to real4 and fp is short for the fpu stack |
costy Author 05. Jul 2008 | msvbvm60 is the reason why people hate vb crackmes. I think that Microsoft has no reason to document this library. |
costy Author 06. Jul 2008 | So guys it isn't so difficult Why nobody write a solution?? |
TiGa 06. Jul 2008 | costy, please stop harassing the members. They will write a solution if and when they want to. |
costy Author 06. Jul 2008 | Sorry Tiga... and sorry members. Next time i will be patient. |
sd333221 07. Jul 2008 | Solution added :-) |
costy Author 07. Jul 2008 | @Xspider I'm happy you liked it. I hope to do some more difficult crackmes. <Just a bit more difficult :-)> Anyway I don't understand how you understood that the shape1(1) must be placed in the shape2(1) shape1(2) must be placed in the shape2(2) shape1(3) must be placed in the shape2(3) ... shape1(10) must be placed in the shape2(10). You only explained how you understood witch index has the red shape, the blue one... Could you explain better?? |
Xspider 07. Jul 2008 | will when you put them all together you will see that the last own [orange shape] is the 1st and 1st [Red] is the last!! sorry 4 my bad english! |
sd333221 07. Jul 2008 | Me and Zaphod took the identical way :-( Didn't have to write a solution if I knew it |
GENNADY22 25. Jul 2008 | Very good crackme :) |
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