BunnX's wizzard Crackme
| Download wizzardCrackme.zip, 125 kb (password: crackmes.de) Browse contents of wizzardCrackme.zip wizzard Crackme
Difficulty: 3 - Getting harder | RatingVotes: 3 View profile of BunnX » |
Solutions
Solution by iSSoGoo, published 18. jun, 2013; download (58 kb), password: crackmes.de or browse.
iSSoGoo has rated this crackme as quite nice.
Solution by neo85, published 18. jun, 2013; download (162 kb), password: crackmes.de or browse.
neo85 has rated this crackme as quite nice.
Discussion and comments
| korsader 13. Jun 2013 | The crackme has a unique solution, or there may be many? I found only one correct value |
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| BunnX Author 13. Jun 2013 | Do you mean one correct key? No, there are many. I wrote a keygen :) |
| BunnX Author 13. Jun 2013 | You can send me a pm, I want to know what value you have found. |
| neo85 14. Jun 2013 | Nice demo scene, I'm writing the solution for this crackme :) |
| BunnX Author 14. Jun 2013 | @neo85 Thank you :) Because I got some pm's, I will clarify something for all who are trying it/ will try it.. There a more serials than one. This single hash value, is the one from a empty string. I only forget to check the length of the second serial section. The right solution have to create a keyfile with a random string or of a inputted name. So it can produce many keys. I'm sorry about that ambiguity. |
| B@zz! 16. Jun 2013 | I've found the key pattern. I think my first part is correct but the second is wrong... 75EF0226-ªªªªªªªªªªªªªªªª I think i need some time for the second part.. and myeb it's something like: c_data_f => first part c_data_s => second part void encrypt_first_part(char* c_data_f, char* c_data_s) { BYTE* b_data_f = (BYTE*)c_data_f; BYTE* b_data_s = (BYTE*)c_data_s; int i = 0; int len = strlen(c_data); bool b_check = false; while(i <= len) { b_data_f[i] ^= c_data_s[i]; if(b_data_f[i]) b_check = true; i++; } } Maybe i'm totally wrong then i'm sorry. |
| zaawrt 16. Jun 2013 | i've done the key file, take a look |
| BunnX Author 16. Jun 2013 | @B@zz! more wrong, sry. @zaawrt I don't know how to grasp your comment. There is not 'the' key file. You should make a gen that's able to produce many different key files. The solution with this 8 Byte Hex string isn't the expected. Maybe I misinterpreted this, you can send me a pm and I will check it. |
| BunnX Author 16. Jun 2013 | Btw, I know it's working this way and so it can be cracked easily. It was my failure that it's not checking the second string for the length. But the challenge is still a keygen for random keys. :\ |
| BunnX Author 19. Jun 2013 | Thanks to neo85 and iSSoGoo for the nice solutions. It's everytime fun to see how people crack my "mind stuff" and good for improving my own skills. |
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